What is the angular acceleration of the fishing reel?
Written by Josh on September 24, 2009 – 4:09 pm -
How much fish pulls the line from the reel in 0.35 s? A fish takes the bait and pulls the line with a force of 2.3 N. The fishing reel, which runs without friction, is a uniform cylinder radius of 0040 m. and 0.94 kilograms masses
Tags: Fishing Reel, Friction, Radius
Posted in FAQs |
By odu83 on Sep 25, 2009 | Reply
This is a solid cylinder or a hollow cylinder? For the solid, I = m * r ^ 2 / 2. If cavity, I = m * r ^ 2 Assume that is solid. If not, recalculated simply with the moment of inertia different. 2.3 = 0.94 * 0040 * 0040 * ^ 2 Î ± / 2 to solve Î ± Î ± = 2 * 2.3 * / (0.94 * 0040) 122 rad / s ^ 2 angular displacement in 0.35 seconds .5 * 122 * 0.35 ^ 2 rad 7.47 rad anmount the line is pulled 7.47 * 2 * Ï? * 0040 1.88 m. ______________________ -